Originally Posted by lucid
The equation that relates power to torque is simple:
Hp = ( Tq x rpm ) / 5252 as long as Tq is measured in lb x ft
So if the tq gains decrease, but the rpm increase, the power gains can be relatively stable, which is what is happening at higher rpms.
You can read the tq value of the chart, plug them into the equation above, obtain power, and compare calculated value to value on chart, which is what I've done. The numbers match.
The real question is the loss percentage entered into the dyno.
I don't think he's done the pulleys. He's reflashed the ECU and installed the new exhaust. Those I know he did for sure. Anyway, he'll tell us.
I can add to this that the guys did say that stock curve had a rather large number of dips etc... that they fix. I will try and get you answers for the questions above, but again, the car is definetly faster from the get go. Its fun as hell to drive!! lol!